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Voltage-to-Current Converter Circuit Explained: High-Side Drive Design Example

Jul 07,2025
Page Views: 51
Author: AXTEK Technology Company Limited

Voltage-to-current (V/I) conversion circuits are widely used in industrial environments, especially in 4–20 mA current loop systems. In this article, we will walk through the working principle and practical design of a high-side V/I converter circuit with a real-world example.

1. Principle of High-Side V/I Converter

This high-side V/I conversion circuit provides a controllable current to a grounded load. It consists of a two-stage architecture:

  • Stage 1: Converts the input voltage (VIN) into a current reference using an op-amp and NMOS.

  • Stage 2: Uses a second op-amp to control the gate of a PMOS, thereby regulating the output current to the load.

The V-I transfer function is determined by the relationship between the input voltage VIN and three current-sensing resistors RS1, RS2, and RS3:

  • Stage 1:

    VRS1=VINIRS1=VINRS1V_{RS1} = V_{IN} \quad → \quad I_{RS1} = \frac{V_{IN}}{R_{S1}}VRS1=VIN→IRS1=RS1VIN

  • Stage 2:

    IRS2IRS1,VRS3VRS2,ILOADIRS3I_{RS2} ≈ I_{RS1}, \quad V_{RS3} ≈ V_{RS2}, \quad I_{LOAD} ≈ I_{RS3}IRS2≈IRS1,VRS3≈VRS2,ILOAD≈IRS3

  • Overall transfer function:

    ILOAD=VINRS1×RS3RS2I_{LOAD} = \frac{V_{IN}}{R_{S1}} × \frac{R_{S3}}{R_{S2}}ILOAD=RS1VIN×RS2RS3

2. Practical Design Example

Design Goal:

  • Supply Voltage: 5V DC

  • Input Voltage Range: 0–2V DC

  • Output: 4.5V / 0–100 mA current

  • Efficiency: ≥ 98%

  • Gain Error: ≤ 0.1%


2.1 Key Component Calculations

a. Designing RS1:

The first stage doesn't drive the load directly, so its power consumption affects overall efficiency. To limit losses and leave headroom for the op-amp's quiescent current, we set the first stage current (IRS1) to 1 mA when the output is at full-scale 100 mA.

  • Max VIN = 2V, so:

    RS1=2V1mA=2kΩR_{S1} = \frac{2V}{1mA} = 2kΩRS1=1mA2V=2kΩ

b. Designing RS2 and RS3:

The second stage generates the output current to the load. Assuming the PMOS drop (VDS) is ~0.3V and aiming for 4.5V across the load (given 5V supply), the voltage across RS3 should be ~470 mV.

  • For IRS2 ≈ 1 mA:

    RS2=470mV1mA=470ΩR_{S2} = \frac{470mV}{1mA} = 470ΩRS2=1mA470mV=470Ω

  • For ILOAD = 100 mA:

    RS3=470mV100mA=4.7ΩR_{S3} = \frac{470mV}{100mA} = 4.7ΩRS3=100mA470mV=4.7Ω

c. Op-Amp Compensation: R2/R3/C6 and R4/R5/C7

Both op-amp stages require compensation to maintain stability. Driving capacitive loads like MOSFET gates can cause oscillation. This design uses a dual-feedback loop, a classic topology that stabilizes the output. For detailed implementation, refer to the technical notes on dual feedback compensation.

2.2 Component Selection Guidelines

ComponentSelection CriteriaNotes
Op-AmpLow offset, low drift, rail-to-rail I/Oe.g., TI OPA192, OPA2333; ADI ADA4522
MOSFETLow threshold (VGS(th)), high current ratinge.g., IRLML6402, IRLML6344
Current-Sense Resistors0.1% tolerance, low temperature coefficientEssential for gain accuracy ≤ 0.1%


⚠️ Note: RS1 accuracy is especially critical, since its error is multiplied by the gain ratio RS3/RS2 and directly affects output current.

3. Conclusion

This two-stage high-side V/I converter design offers a precise and efficient method to translate a low-voltage analog input into a regulated current output for grounded loads. It is well-suited for applications such as:

  • Industrial sensor excitation

  • Analog signal transmission over long distances

  • Programmable current sources


With careful selection of op-amps, MOSFETs, and precision resistors, the circuit achieves:

√   High efficiency (≥98%)
√   Low gain error (≤0.1%)
√   Stable operation under capacitive load


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